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EXAMPLE 5. The reaction of cyanamide NH_{2}CN(s) with dioxygen was carried out in a bomb calorimeter, and Al was found to be-742.7 kJ mol at 298 K. Calculate the enthalpy change for the reaction at 298 K (R=8.314\times10^{-3}kJK^{-1}mol^{-1}) , NH₂CN()+ O2(g) N_{2}(g)+CO_{2}(g)+H_{2}O(l)? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared
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the Class 11 exam syllabus. Information about EXAMPLE 5. The reaction of cyanamide NH_{2}CN(s) with dioxygen was carried out in a bomb calorimeter, and Al was found to be-742.7 kJ mol at 298 K. Calculate the enthalpy change for the reaction at 298 K (R=8.314\times10^{-3}kJK^{-1}mol^{-1}) , NH₂CN()+ O2(g) N_{2}(g)+CO_{2}(g)+H_{2}O(l)? covers all topics & solutions for Class 11 2024 Exam.
Find important definitions, questions, meanings, examples, exercises and tests below for EXAMPLE 5. The reaction of cyanamide NH_{2}CN(s) with dioxygen was carried out in a bomb calorimeter, and Al was found to be-742.7 kJ mol at 298 K. Calculate the enthalpy change for the reaction at 298 K (R=8.314\times10^{-3}kJK^{-1}mol^{-1}) , NH₂CN()+ O2(g) N_{2}(g)+CO_{2}(g)+H_{2}O(l)?.
Solutions for EXAMPLE 5. The reaction of cyanamide NH_{2}CN(s) with dioxygen was carried out in a bomb calorimeter, and Al was found to be-742.7 kJ mol at 298 K. Calculate the enthalpy change for the reaction at 298 K (R=8.314\times10^{-3}kJK^{-1}mol^{-1}) , NH₂CN()+ O2(g) N_{2}(g)+CO_{2}(g)+H_{2}O(l)? in English & in Hindi are available as part of our courses for Class 11.
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Here you can find the meaning of EXAMPLE 5. The reaction of cyanamide NH_{2}CN(s) with dioxygen was carried out in a bomb calorimeter, and Al was found to be-742.7 kJ mol at 298 K. Calculate the enthalpy change for the reaction at 298 K (R=8.314\times10^{-3}kJK^{-1}mol^{-1}) , NH₂CN()+ O2(g) N_{2}(g)+CO_{2}(g)+H_{2}O(l)? defined & explained in the simplest way possible. Besides giving the explanation of
EXAMPLE 5. The reaction of cyanamide NH_{2}CN(s) with dioxygen was carried out in a bomb calorimeter, and Al was found to be-742.7 kJ mol at 298 K. Calculate the enthalpy change for the reaction at 298 K (R=8.314\times10^{-3}kJK^{-1}mol^{-1}) , NH₂CN()+ O2(g) N_{2}(g)+CO_{2}(g)+H_{2}O(l)?, a detailed solution for EXAMPLE 5. The reaction of cyanamide NH_{2}CN(s) with dioxygen was carried out in a bomb calorimeter, and Al was found to be-742.7 kJ mol at 298 K. Calculate the enthalpy change for the reaction at 298 K (R=8.314\times10^{-3}kJK^{-1}mol^{-1}) , NH₂CN()+ O2(g) N_{2}(g)+CO_{2}(g)+H_{2}O(l)? has been provided alongside types of EXAMPLE 5. The reaction of cyanamide NH_{2}CN(s) with dioxygen was carried out in a bomb calorimeter, and Al was found to be-742.7 kJ mol at 298 K. Calculate the enthalpy change for the reaction at 298 K (R=8.314\times10^{-3}kJK^{-1}mol^{-1}) , NH₂CN()+ O2(g) N_{2}(g)+CO_{2}(g)+H_{2}O(l)? theory, EduRev gives you an
ample number of questions to practice EXAMPLE 5. The reaction of cyanamide NH_{2}CN(s) with dioxygen was carried out in a bomb calorimeter, and Al was found to be-742.7 kJ mol at 298 K. Calculate the enthalpy change for the reaction at 298 K (R=8.314\times10^{-3}kJK^{-1}mol^{-1}) , NH₂CN()+ O2(g) N_{2}(g)+CO_{2}(g)+H_{2}O(l)? tests, examples and also practice Class 11 tests.