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EXAMPLE 5. The reaction of cyanamide NH_{2}CN(s) with dioxygen was carried out in a bomb calorimeter, and Al was found to be-742.7 kJ mol at 298 K. Calculate the enthalpy change for the reaction at 298 K (R=8.314\times10^{-3}kJK^{-1}mol^{-1}) , NH₂CN()+ O2(g) N_{2}(g)+CO_{2}(g)+H_{2}O(l)?
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EXAMPLE 5. The reaction of cyanamide NH_{2}CN(s) with dioxygen was car...
Given:
- Reaction: NH₂CN(s) + O₂(g) → N₂(g) + CO₂(g) + H₂O(l)
- Enthalpy change: ΔH = -742.7 kJ/mol
- Temperature: 298 K
- Gas constant: R = 8.314 × 10^(-3) kJ K^(-1) mol^(-1)

To Find:
Enthalpy change for the reaction at 298 K.

Calculations:
The enthalpy change for a reaction can be calculated using the equation:
ΔH = ΔU + ΔnRT

Where:
ΔH = Enthalpy change
ΔU = Change in internal energy
Δn = Change in the number of moles of gaseous products and reactants
R = Gas constant
T = Temperature

Step 1: Calculate Δn
- In the reaction, there are 2 moles of gaseous products (N₂ and CO₂) and 3 moles of gaseous reactants (O₂).
- Δn = (2 - 3) = -1

Step 2: Calculate ΔU
- The reaction is carried out in a bomb calorimeter, which measures the change in heat at constant volume. Therefore, the change in internal energy (ΔU) is equal to the heat released or absorbed by the reaction.
- ΔU = -742.7 kJ/mol

Step 3: Calculate ΔH
- Using the equation ΔH = ΔU + ΔnRT, we can substitute the values to calculate ΔH.
- ΔH = -742.7 kJ/mol + (-1) × (8.314 × 10^(-3) kJ K^(-1) mol^(-1)) × (298 K)
- ΔH = -742.7 kJ/mol - 2.4708 kJ/mol
- ΔH = -745.1708 kJ/mol

Answer:
The enthalpy change for the reaction at 298 K is -745.1708 kJ/mol.
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EXAMPLE 5. The reaction of cyanamide NH_{2}CN(s) with dioxygen was carried out in a bomb calorimeter, and Al was found to be-742.7 kJ mol at 298 K. Calculate the enthalpy change for the reaction at 298 K (R=8.314\times10^{-3}kJK^{-1}mol^{-1}) , NH₂CN()+ O2(g) N_{2}(g)+CO_{2}(g)+H_{2}O(l)?
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EXAMPLE 5. The reaction of cyanamide NH_{2}CN(s) with dioxygen was carried out in a bomb calorimeter, and Al was found to be-742.7 kJ mol at 298 K. Calculate the enthalpy change for the reaction at 298 K (R=8.314\times10^{-3}kJK^{-1}mol^{-1}) , NH₂CN()+ O2(g) N_{2}(g)+CO_{2}(g)+H_{2}O(l)? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about EXAMPLE 5. The reaction of cyanamide NH_{2}CN(s) with dioxygen was carried out in a bomb calorimeter, and Al was found to be-742.7 kJ mol at 298 K. Calculate the enthalpy change for the reaction at 298 K (R=8.314\times10^{-3}kJK^{-1}mol^{-1}) , NH₂CN()+ O2(g) N_{2}(g)+CO_{2}(g)+H_{2}O(l)? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for EXAMPLE 5. The reaction of cyanamide NH_{2}CN(s) with dioxygen was carried out in a bomb calorimeter, and Al was found to be-742.7 kJ mol at 298 K. Calculate the enthalpy change for the reaction at 298 K (R=8.314\times10^{-3}kJK^{-1}mol^{-1}) , NH₂CN()+ O2(g) N_{2}(g)+CO_{2}(g)+H_{2}O(l)?.
Solutions for EXAMPLE 5. The reaction of cyanamide NH_{2}CN(s) with dioxygen was carried out in a bomb calorimeter, and Al was found to be-742.7 kJ mol at 298 K. Calculate the enthalpy change for the reaction at 298 K (R=8.314\times10^{-3}kJK^{-1}mol^{-1}) , NH₂CN()+ O2(g) N_{2}(g)+CO_{2}(g)+H_{2}O(l)? in English & in Hindi are available as part of our courses for Class 11. Download more important topics, notes, lectures and mock test series for Class 11 Exam by signing up for free.
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